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JEE Adv 2026: "Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the..."| Maths Paper 1 Solution
Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the slope of the tangent to the parabola at the
point 𝑃 is 4 . Let 𝑄 be the point in the first quadrant lying on the circle 𝑥2+𝑦2=2 such that the
slope of the tangent to the circle at the point 𝑄 is −1 . Let 𝑅 be the point in the first quadrant lying
on the ellipse 𝑥2+4𝑦2=8 such that the slope of the tangent to the ellipse at the point 𝑅 is −1
2
.
Then the radius of the circle passing through the points 𝑃,𝑄 and 𝑅 is:
If you found this solution helpful, make sure to check out my channel for the rest of the JEE Advanced 2026 Paper 1 solutions!
#JEEAdvanced2026 #JEEMaths #IITJEE #JEEPrep #JEEAdvancedSolutions
Видео JEE Adv 2026: "Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the..."| Maths Paper 1 Solution канала Shaurya Agarwal
point 𝑃 is 4 . Let 𝑄 be the point in the first quadrant lying on the circle 𝑥2+𝑦2=2 such that the
slope of the tangent to the circle at the point 𝑄 is −1 . Let 𝑅 be the point in the first quadrant lying
on the ellipse 𝑥2+4𝑦2=8 such that the slope of the tangent to the ellipse at the point 𝑅 is −1
2
.
Then the radius of the circle passing through the points 𝑃,𝑄 and 𝑅 is:
If you found this solution helpful, make sure to check out my channel for the rest of the JEE Advanced 2026 Paper 1 solutions!
#JEEAdvanced2026 #JEEMaths #IITJEE #JEEPrep #JEEAdvancedSolutions
Видео JEE Adv 2026: "Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the..."| Maths Paper 1 Solution канала Shaurya Agarwal
jee advanced math coordinate geometry jee advanced tangent to parabola tangent to ellipse tangent to circle slope form radius of circumcircle of triangle points on conic sections jee math tricks circumcircle right angled triangle jee advanced 2026 math iit jee coordinate geometry math paper solution
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20 мая 2026 г. 17:26:32
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