Загрузка...

JEE Adv 2026: "Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the..."| Maths Paper 1 Solution

Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the slope of the tangent to the parabola at the
point 𝑃 is 4 . Let 𝑄 be the point in the first quadrant lying on the circle 𝑥2+𝑦2=2 such that the
slope of the tangent to the circle at the point 𝑄 is −1 . Let 𝑅 be the point in the first quadrant lying
on the ellipse 𝑥2+4𝑦2=8 such that the slope of the tangent to the ellipse at the point 𝑅 is −1
2
.
Then the radius of the circle passing through the points 𝑃,𝑄 and 𝑅 is:
If you found this solution helpful, make sure to check out my channel for the rest of the JEE Advanced 2026 Paper 1 solutions!

#JEEAdvanced2026 #JEEMaths #IITJEE #JEEPrep #JEEAdvancedSolutions

Видео JEE Adv 2026: "Let 𝑃 be the point on the parabola 𝑦=𝑥2 such that the..."| Maths Paper 1 Solution канала Shaurya Agarwal
Яндекс.Метрика
Все заметки Новая заметка Страницу в заметки
Страницу в закладки Мои закладки
На информационно-развлекательном портале SALDA.WS применяются cookie-файлы. Нажимая кнопку Принять, вы подтверждаете свое согласие на их использование.
О CookiesНапомнить позжеПринять