Minimum Insertion Steps to Make a String Palindrome | LPS Trick + Interval DP | Part 212 [Hindi]

📘 Welcome to Part 212 of Code & Debug’s DSA in Python Course! This session solves “Minimum Insertion Steps to Make a String Palindrome.” The key insight: the fewest insertions equals n − LPS(s), where LPS is the Longest Palindromic Subsequence length. We’ll cover both the elegant LCS/LPS reduction and the classic interval DP formulation, with complete Python walkthroughs.

🔗 LeetCode – Minimum Insertion Steps to Make a String Palindrome:
https://leetcode.com/problems/minimum-insertion-steps-to-make-a-string-palindrome/description/

🔗 Companion Reading (LPS/LCS approach and interval DP):
https://codeanddebug.in/blog/minimum-insertion-steps-to-make-a-string-palindrome/

📄 FULL Playlist Sheet (All Videos in Order):
https://docs.google.com/spreadsheets/d/1AWE15Fy3wD2iqu2vjK_R7cCiuvSsjYQclcdZmHpF66o/edit?usp=sharing

🎓 Enroll Free: Master Python DSA Course
https://codeanddebug.in/course/master-dsa-with-leetcode

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https://codeanddebug.in/course/zero-to-hero-python-dsa

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